How To Solve Angle Relationships
Bending RELATIONSHIPS
2 or more angles can be related, if sure conditions are met. Hither, we will learn different types of bending relationships.
(i) Congruent Angles
(ii) Vertical Angles
(iii) Complementary Angles
(4) Supplementary Angles
(v) Side by side Angles
(vi) Side by side Angles in Parallelogram
(vii) Linear Pair
(viii) Corresponding Angles
(ix) Alternate Interior Angles
(x) Alternate Exterior Angles
(xi) Sequent Interior Angles
(xii) Consecutive Outside Angles
Allow the states see the above dissimilar types of bending relationships in detail.
(i) Congruent Angles :
Congruent angles are angles that take the same measure.
(ii) Vertical Angles :
Vertical angles take a mutual vertex, but they are never adjacentangles. And also,vertical angles are e'er congruent.
(iii) Complementary Angles :
If the sum of two angles is 90⁰, then those two angles are called as complementary angles.
(iv) Supplementary Angles :
If the sum of two angles is 180 ° , and so those two angles are called equally supplementary angles.
(five) Side by side Angles :
Side by side angles are two angles that have a common vertex and a common side.
(half dozen) Consecutive Angles in Parallelogram :
Any 2 consecutive angles of a parallelogram are supplementary.
(vii) Linear Pair :
A linear pair is a pair of adjacent angles formed when ii lines intersect.
The 2 angles of a linear pair are always supplementary , which means their measures add up to 180°.
In the figure above A and B are linear pair.
A + B = 180 °
To know nigh Corresponding Angles, Alternate Interior Angles, Alternating Exterior Angles, Sequent Interior Angles and Consecutive Outside Angles in item,
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Solved Questions
Questions 1-vii : Discover the value of 10 in the diagram.
Question 1 :
Answer :
In the diagram above, (6x + 4)° and (4x + 6)° are complementary.
(6x + iv)° + (4x + vi)° = 90°
6x + four + 4x + 6 = xc
10x + 10 = 90
10x = 80
x = 8
Question 2 :
Answer :
In the diagram above, (4x + seven)° and (6x + 3)° are complementary.
(4x + 7)° + (6x + 3)° = 90°
4x + vii + 6x + 3 = 90
10x + x = 90
10x = 80
x = 8
Question 3 :
Respond :
In the diagram above, (2x + 3)° and (x - 6)° are supplementary angles.
(2x + 3)° + (10 - 6)° = 180°
2x + 3 + x - half-dozen = 180
3x - 3 = 180
3x = 183
x = 61
Question iv :
Respond :
In the diagram above, (5x + iv)°, (10 - 2)° and (3x + 7)° are supplementary angles.
(5x + four)° + (x - two)° + (3x + 7)° = 180°
5x + 4 + x -2 + 3x + 7 = 180
9x + 9 = 180
9x = 171
10 = 19
Question 5 :
Answer :
In the diagram above, (3x + 7)° and 100° are vertical angles.
(3x + 7)° = 100°
3x + 7 = 100
3x = 93
10 = 31
Question half dozen :
Respond :
In the diagram above, (10 + 33)° and 98° form a linear pair.
(ten + 33)° + 98° = 180°
x + 33 + 98 = 180
ten + 131 = 180
ten = 49
Question vii :
In the diagram given beneath, lilines 50ii are parallel and t is a transversal. Find the value of x.
Answer :
In the above diagram, (2x + 20) ° and (3x - 10) ° are respective angles.
When 2 parallel lines are cut by a transversal, corresponding angles are coinciding.
(2x + twenty)° = (3x - 10)°
2x + twenty = 3x - ten
30 = x
Question eight :
In the diagram given below, l1lines 50two are parallel and t is a transversal. Detect the value of x.
Answer :
In the above diagram, (2x + x)° and (x + 5)° are sequent interior angles.
When 2 parallel lines are cutting by a transversal, consecutive interior angles are supplementary.
(2x + 10)° + (x + 5)° = 180 °
2x + 10 + x + 5 = 180
3x + 15 = 180
3x = 165
ten = 55
Question 9 :
In the diagram given below, lines a and b are parallel and t is a transversal. Notice the value of ten.
Answer :
In the diagram diagram, (2x + 26)° and (3x - 33)° are alternate interior angles.
When 2 parallel lines are cut past a transversal, alternate interior angles are congruent.
(2x + 26)° = (3x - 33) °
2x + 26 = 3x - 33
59 = x
Question 10 :
In the diagram shown beneath, f ind the value of x.
Respond :
In the diagram diagram, it is articulate that AB||CD and Advertizement||BC.
So ABCD is a parallelogram.
In a parallelogram, two consecutive angles are always supplementary.
10° + (2x)° = 180 °
ten + 2x = 180
3x = 180
x = lx
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How To Solve Angle Relationships,
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